Master Aptitude for IT Placements

Your complete guide to cracking quantitative aptitude & logical reasoning in TCS, Infosys, Wipro, Cognizant, Accenture and more.

0
Topics Covered
0
Solved Examples
0
Shortcuts & Tricks
0
Formula Cards
🎯 What is Aptitude?

Aptitude is the innate or acquired ability to solve problems using logic, reasoning, and mathematical skills. In IT campus placements, aptitude tests are the first and most critical filter — companies use them to shortlist candidates before technical rounds and interviews.

💡 Why It Matters

In most IT companies, 60-70% of candidates are eliminated in the aptitude round alone. A strong aptitude score doesn't just get you through — it gives you confidence for the rest of the process.

What Aptitude Tests Evaluate

  • Speed — Can you solve problems under time pressure? (typically 1-2 min per question)
  • Accuracy — Many exams have negative marking for wrong answers
  • Problem-solving approach — Can you identify patterns and pick the right method?
  • Numerical reasoning — Basic to intermediate math with practical application
  • Logical thinking — Pattern recognition, deduction, and analytical skills

Three Pillars of Placement Aptitude

PillarTopicsWeight
Quantitative AptitudeNumbers, Percentages, Profit/Loss, Time & Work, Speed, Probability, etc.~50-60%
Logical ReasoningCoding-Decoding, Blood Relations, Seating, Puzzles, Syllogisms~25-30%
Verbal AbilityReading Comprehension, Grammar, Vocabulary (not covered here)~15-20%
🧠 How to Approach Aptitude Problems

The 5-Step Framework

1
Read Carefully — Identify what is given, what is asked, and what type of problem it is. 80% of mistakes come from misreading the question.
2
Classify the Problem — Mentally map it to a category (percentage? time & work? probability?). This instantly narrows your toolkit.
3
Pick the Right Method — Use shortcuts first, algebraic approach as backup. If options are given, consider plugging in answers.
4
Solve & Verify — Do the calculation. Check if your answer makes logical sense (e.g., speed can't be negative, probability can't exceed 1).
5
Manage Time — If stuck for more than 90 seconds, mark and move on. Come back later with fresh eyes.
⚡ Golden Rules for Speed
  • Options are your friend — Work backwards from answers; plug-in is faster than algebra
  • Approximation wins — If choices are spread apart, round numbers and estimate
  • Unit digit analysis — Eliminate options by checking only the last digit of your calculation
  • Memorize key values — Squares (1-30), cubes (1-15), fraction-to-% conversions, powers of 2
  • LCM method over fractions — Converts fractional work-rate problems to whole-number arithmetic
Speed-Solving Strategies

Strategy 1: Work Backward from Answer Choices

In MCQ exams, start with option B or C (middle value) and plug it into the question. This eliminates half the options instantly.

Strategy 2: Unit Digit Analysis

If answer choices have different last digits, calculate only the unit digit of the expression.

🔢 Unit Digit Cycles for Powers
Base ending inCycle of unit digitsPeriod
22, 4, 8, 64
33, 9, 7, 14
44, 62
77, 9, 3, 14
88, 4, 2, 64
0, 1, 5, 6Same digit always1
99, 12

Strategy 3: Vedic Math Multiplication

⚡ Multiply by 11

For AB × 11: Write A_(A+B)_B. Carry over if sum ≥ 10.

Example: 34 × 11 = 3_(3+4)_4 = 374

Example: 85 × 11 = 8_(13)_5 = 935 (carry the 1)

⚡ Squaring Numbers Ending in 5

For N5²: Multiply N × (N+1), append 25.

Example: 35² = 3×4 = 12, append 25 → 1225

Example: 75² = 7×8 = 56, append 25 → 5625

⚡ Squaring Numbers Near 100 (Nikhilam Method)

Let d = N − 100. Then N² = (N + d) concatenated with d² (as 2 digits).

Example: 96²: d = −4. First part: 96−4 = 92. Last: 16. Answer = 9216

Example: 104²: d = +4. First: 104+4 = 108. Last: 16. Answer = 10816

⚡ Multiplying Numbers Near 100

For A × B near 100: Let da = A−100, db = B−100. Result = (A+db) | (da×db)

Example: 97 × 96: da=−3, db=−4. First: 97−4=93. Last: 12. Answer = 9312

Example: 103 × 105: da=3, db=5. First: 103+5=108. Last: 15. Answer = 10815

Strategy 4: Divisibility Rules

Divisible byQuick Check
2Last digit is even
3Sum of digits divisible by 3
4Last two digits divisible by 4
5Last digit is 0 or 5
6Divisible by both 2 and 3
8Last three digits divisible by 8
9Sum of digits divisible by 9
11Difference of sum of alternate digits divisible by 11

Strategy 5: Remainder Shortcut

🔢 Formula
Remainder of (a × b × c) ÷ n = [rem(a/n) × rem(b/n) × rem(c/n)] mod n

Example: Remainder of (17 × 23 × 49) ÷ 12:
17 mod 12 = 5, 23 mod 12 = 11, 49 mod 12 = 1
Product = 5 × 11 × 1 = 55. Then 55 mod 12 = 7

Strategy 6: Multiply/Divide by 5, 25, 50, 125

Multiply byShortcutExample
×5÷2, then ×1048×5 = 24×10 = 240
×25÷4, then ×10048×25 = 12×100 = 1200
×50÷2, then ×10048×50 = 24×100 = 2400
×125÷8, then ×100048×125 = 6×1000 = 6000

Key Values to Memorize

🔢 Squares (1–30)

1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625, 676, 729, 784, 841, 900

🔢 Cubes (1–15)

1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, 1331, 1728, 2197, 2744, 3375

🔢 Powers of 2

1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096

🔢 Fraction ↔ Percentage
Fraction%Fraction%Fraction%
1/250%1/616.67%1/119.09%
1/333.33%1/714.28%1/128.33%
1/425%1/812.5%1/156.67%
1/520%1/911.11%1/205%
🔢 01 — Number Systems

Number system questions test your understanding of LCM, HCF, divisibility, remainders, and properties of numbers. These form the foundation of all quantitative aptitude.

TCS Infosys Wipro Cognizant All Companies

Key Concepts

🔢 Core Formulas
LCM × HCF = Product of the two numbers
LCM(a,b) = (a × b) / HCF(a,b)

LCM = Least Common Multiple (smallest number divisible by both)
HCF/GCD = Highest Common Factor (largest number that divides both)

⚡ Shortcuts
  • LCM of fractions: LCM of numerators / HCF of denominators
  • HCF of fractions: HCF of numerators / LCM of denominators
  • Co-prime numbers: HCF = 1, so LCM = product
  • For 3+ numbers: Find LCM/HCF of two at a time

Example 1: LCM & HCF Application

📝 Solved Example

Q: Find the smallest number which when divided by 12, 15, and 20 leaves a remainder of 5 in each case.

1
Identify: The number leaves the SAME remainder (5) when divided by 12, 15, and 20. So (Number − 5) is exactly divisible by all three.
2
Find LCM(12, 15, 20):
12 = 2² × 3
15 = 3 × 5
20 = 2² × 5
LCM = 2² × 3 × 5 = 60
3
Answer: Smallest number = LCM + remainder = 60 + 5 = 65
💡 Pattern

Same remainder → LCM + remainder. Different remainders → LCM − (divisor − remainder) pattern.

Example 2: HCF Application

📝 Solved Example

Q: Two tankers contain 850 litres and 680 litres of fuel. Find the maximum capacity of a container that can measure the fuel of both tankers exactly.

1
Identify: "Maximum capacity that measures both exactly" = HCF of 850 and 680.
2
Euclid's Method:
850 = 680 × 1 + 170
680 = 170 × 4 + 0
HCF = 170 litres
3
Verify: 850 ÷ 170 = 5 (exact). 680 ÷ 170 = 4 (exact). ✔
% 02 — Percentages

Percentages are the backbone of profit/loss, interest, data interpretation, and more. Mastering percentage conversions makes you fast at almost everything else.

All Companies
🔢 Core Formulas
Percentage = (Part / Whole) × 100
% Change = [(New − Old) / Old] × 100
Successive change: Net% = a + b + (ab/100)
⚡ Key Shortcuts
  • X% of Y = Y% of X — Pick whichever is easier! (8% of 50 = 50% of 8 = 4)
  • Break it down: 17.5% = 10% + 5% + 2.5%
  • If A is 25% more than B, then B is 20% less than A (reciprocal pair)
A more than B byB less than A by
10%9.09%
20%16.67%
25%20%
33.33%25%
50%33.33%

Example 1: Successive Percentage Change

📝 Solved Example

Q: The price of a laptop increases by 20% and then decreases by 20%. What is the net percentage change?

1
Apply formula: Net% = a + b + (ab/100)
Here a = +20, b = −20
2
Net% = 20 + (−20) + (20 × −20)/100 = 0 + (−400/100) = −4%
3
Answer: The price decreases by 4% (NOT zero!). This is a classic trap question.
⚠ Common Trap

Many students assume +20% then −20% = no change. It's always a net LOSS. Remember: increase then same decrease always gives net loss of (x²/100)%.

Example 2: Population/Increase Problem

📝 Solved Example

Q: A town's population is 50,000. It increases by 10% in the first year and 20% in the second year. What is the population after 2 years?

1
Method 1 (Step-by-step):
After year 1: 50,000 × 1.10 = 55,000
After year 2: 55,000 × 1.20 = 66,000
2
Method 2 (Net change):
Net% = 10 + 20 + (10×20/100) = 32%
Population = 50,000 × 1.32 = 66,000
💰 03 — Profit & Loss

Profit & Loss questions revolve around Cost Price (CP), Selling Price (SP), Marked Price (MP), and discounts. Very frequently asked in TCS and Cognizant.

TCS Cognizant Accenture
🔢 Core Formulas
Profit% = [(SP − CP) / CP] × 100
SP = CP × (100 + Profit%) / 100
Discount% = [(MP − SP) / MP] × 100
Net Profit% = Markup% − Discount% − (Markup% × Discount%) / 100
⚡ Shortcuts
  • CP of X items = SP of Y items: Profit% = [(X−Y)/Y] × 100
  • False weight: Profit% = [(True − False) / False] × 100
  • Two successive discounts d1% and d2%: Equivalent = d1 + d2 − (d1×d2/100)

Example 1: Markup & Discount

📝 Solved Example

Q: A shopkeeper marks up the price of an article by 40% and then offers a 10% discount. Find his profit percentage.

1
Direct Formula: Net Profit% = Markup% − Discount% − (Markup% × Discount%)/100
2
= 40 − 10 − (40 × 10)/100 = 40 − 10 − 4 = 26%
3
Verification: Let CP = 100. MP = 140. SP = 140 × 0.9 = 126. Profit = 26%. ✔

Example 2: CP of X = SP of Y

📝 Solved Example

Q: The cost price of 25 articles is equal to the selling price of 20 articles. Find the profit percentage.

1
Apply shortcut: Profit% = [(X − Y) / Y] × 100 where X = 25, Y = 20
2
= [(25 − 20) / 20] × 100 = (5/20) × 100 = 25%
🏦 04 — Simple & Compound Interest

Interest problems appear in almost every placement exam. The key is knowing when to use SI vs CI formulas and the shortcuts that save time.

TCS Infosys All Companies
🔢 Core Formulas
Simple Interest: SI = (P × R × T) / 100
Compound Interest: A = P(1 + R/100)T
CI = A − P = P[(1 + R/100)T − 1]
For 2 years: CI − SI = P(R/100)²
⚡ Shortcuts
  • Rule of 72: Money doubles in 72/R years at compound interest
  • Rule of 114: Money triples in 114/R years
  • At 10% CI for 2 years: Effective rate = 21% (not 20%)
  • Difference between CI and SI for 2 years: CI − SI = P(R/100)²

Example 1: Rule of 72

📝 Solved Example

Q: At what rate of compound interest will Rs. 10,000 double itself in approximately 6 years?

1
Apply Rule of 72: Years to double = 72 / Rate
2
6 = 72 / R ⇒ R = 72/6 = 12% per annum
💡 Quick Recall

8% → 9 years | 10% → 7.2 years | 12% → 6 years | 15% → 4.8 years

Example 2: CI vs SI Difference

📝 Solved Example

Q: The difference between CI and SI on a sum of money at 10% per annum for 2 years is Rs. 50. Find the sum.

1
Use shortcut: CI − SI (for 2 years) = P(R/100)²
2
50 = P × (10/100)² = P × 1/100
3
P = 50 × 100 = Rs. 5,000
05 — Time & Work

Time & Work is one of the most frequently asked topics. The LCM method is a game-changer — it eliminates fractions and makes problems incredibly fast to solve.

TCS Infosys Wipro All Companies
🔢 Core Formulas
If A does a job in 'a' days: A's rate = 1/a per day
A & B together: Time = (a × b) / (a + b) days
MDH Formula: M1D1H1/W1 = M2D2H2/W2
⚡ The LCM Method (Master This!)

Instead of dealing with fractions, take the LCM of all given days as the total units of work. Then each person's daily work becomes a whole number.

  1. Find LCM of all the time periods
  2. Divide LCM by each person's days = their daily work rate (in units)
  3. Add/subtract rates as needed
  4. Time = Total units / Combined rate

Example 1: LCM Method

📝 Solved Example

Q: A can complete a work in 12 days, B in 15 days, and C in 20 days. If all three work together, in how many days will the work be completed?

1
LCM(12, 15, 20) = 60 units (total work)
2
A's rate = 60/12 = 5 units/day
B's rate = 60/15 = 4 units/day
C's rate = 60/20 = 3 units/day
3
Together = 5 + 4 + 3 = 12 units/day
4
Time = 60/12 = 5 days
💡 No Fractions!

Notice how the LCM method converted everything to whole numbers. No messy 1/12 + 1/15 + 1/20 calculations needed!

Example 2: Work & Leaving

📝 Solved Example

Q: A can do a piece of work in 10 days, B in 15 days. They work together for 4 days, then A leaves. How many more days will B take to finish the remaining work?

1
LCM(10, 15) = 30 units
2
A's rate = 30/10 = 3 units/day. B's rate = 30/15 = 2 units/day.
3
In 4 days together: (3+2) × 4 = 20 units done.
4
Remaining = 30 − 20 = 10 units. B alone: 10/2 = 5 more days
🚘 06 — Time, Speed & Distance

Speed-distance problems are about applying the basic relationship D = S × T in clever ways. The average speed trap catches most students.

TCS Infosys Wipro
🔢 Core Formulas
Distance = Speed × Time
km/hr to m/s: multiply by 5/18
Average Speed (equal distances) = 2ab / (a + b)
⚡ Shortcuts
  • Average speed for equal distances is the HARMONIC mean, not arithmetic mean
  • If speed ratio = a:b, time ratio for same distance = b:a
  • Relative speed — Same direction: subtract. Opposite direction: add.
km/hrm/s
3610
5415
7220
9025

Example 1: Average Speed Trap

📝 Solved Example

Q: A person goes from A to B at 40 km/hr and returns at 60 km/hr. Find the average speed for the entire journey.

1
Equal distances → Use harmonic mean: Average = 2ab/(a+b)
2
= 2 × 40 × 60 / (40 + 60) = 4800/100 = 48 km/hr
⚠ Common Trap

The answer is NOT 50 km/hr (which is the arithmetic mean). For equal distances, always use the harmonic mean.

Example 2: Relative Speed

📝 Solved Example

Q: Two people start from two points 120 km apart and walk towards each other at 8 km/hr and 7 km/hr. After how many hours will they meet?

1
Moving towards each other → Relative speed = 8 + 7 = 15 km/hr
2
Time = Distance / Relative speed = 120/15 = 8 hours
🚆 07 — Trains

Train problems are a special case of speed-distance where the length of the train adds to the distance. Remember: a train has to cover its own length to completely pass something.

TCS Wipro
🔢 Master Table
ScenarioDistance to CoverSpeed
Train passes a pole/personLength of trainSpeed of train
Train passes a platform/bridgeLtrain + LplatformSpeed of train
Two trains, opposite directionL1 + L2S1 + S2
Two trains, same directionL1 + L2S1 − S2

Example 1: Train & Platform

📝 Solved Example

Q: A train 200m long runs at 72 km/hr. How long does it take to cross a 300m platform?

1
Convert: 72 km/hr = 72 × 5/18 = 20 m/s
2
Total distance = 200 + 300 = 500m
3
Time = 500/20 = 25 seconds

Example 2: Two Trains Opposite Direction

📝 Solved Example

Q: Two trains of lengths 150m and 250m are moving in opposite directions at 54 km/hr and 36 km/hr. How long to cross each other?

1
Relative speed = 54 + 36 = 90 km/hr = 90 × 5/18 = 25 m/s
2
Total distance = 150 + 250 = 400m
3
Time = 400/25 = 16 seconds
🚰 08 — Pipes & Cisterns

Pipes & Cisterns is essentially Time & Work with one twist: leaks do negative work. Use the same LCM method!

TCS Cognizant
🔢 Core Concept

Filling pipe = positive work. Emptying pipe/leak = negative work.

If pipe fills in 'a' hrs and leak empties in 'b' hrs (b>a): Net time = ab/(b−a)
Leak rate: If fills in 'a' hrs normally, 'b' hrs with leak: Leak empties in ab/(b−a)

Example 1: Three Pipes

📝 Solved Example

Q: Pipe A fills a tank in 12 hours, B fills in 15 hours, C empties in 20 hours. If all three are open, how long to fill the tank?

1
LCM(12, 15, 20) = 60 units
2
A = +5 units/hr, B = +4 units/hr, C = −3 units/hr
3
Net = 5 + 4 − 3 = 6 units/hr. Time = 60/6 = 10 hours

Example 2: Leak Problem

📝 Solved Example

Q: A pipe can fill a tank in 6 hours. Due to a leak, it takes 8 hours. How long will the leak take to empty a full tank?

1
Shortcut: Leak empties in = (a × b)/(b − a) = (6 × 8)/(8 − 6)
2
= 48/2 = 24 hours
📊 09 — Averages

Average questions often appear in combination with data interpretation. The deviation method lets you calculate averages mentally.

Infosys Cognizant All Companies
🔢 Core Formulas
Average = Sum of values / Number of values
Weighted Average = (n1A1 + n2A2) / (n1 + n2)
⚡ Deviation Method (Mental Math)

Pick an assumed mean 'A' near the values. Average = A + (sum of deviations / n).

Example: Average of 48, 52, 55, 47, 53. Assume A = 50.
Deviations: −2, +2, +5, −3, +3 = +5. Average = 50 + 5/5 = 51

Example 1: Replacement

📝 Solved Example

Q: The average age of 30 students is 15 years. If the teacher's age is included, the average increases by 1. What is the teacher's age?

1
Total age of students = 30 × 15 = 450
2
New average = 16, with 31 people. New total = 31 × 16 = 496
3
Teacher's age = 496 − 450 = 46 years

Example 2: Batsman's Average

📝 Solved Example

Q: A batsman has an average of 40 runs in 9 innings. How many runs must he score in the 10th innings to raise his average to 42?

1
Current total = 9 × 40 = 360 runs
2
Required total for avg 42 in 10 innings = 10 × 42 = 420
3
Runs needed = 420 − 360 = 60 runs
💡 Quick Formula

Runs needed = New average + (Number of previous innings × increase) = 42 + 9×2 = 60

10 — Ratio & Proportion

Ratios underpin many other topics (mixtures, ages, work). Mastering ratio manipulation is essential for speed.

TCS Infosys
🔢 Core Formulas
If a:b = c:d, then ad = bc (cross multiplication)
Componendo-Dividendo: (a+b)/(a−b) = (c+d)/(c−d)
Divide N in ratio a:b:c → First part = N × a/(a+b+c)

Example 1: Proportional Division

📝 Solved Example

Q: Divide Rs. 3,600 among A, B, C in the ratio 2:3:4.

1
Total parts = 2 + 3 + 4 = 9. Value of 1 part = 3600/9 = 400
2
A = 2 × 400 = Rs. 800, B = 3 × 400 = Rs. 1200, C = 4 × 400 = Rs. 1600

Example 2: Combining Ratios

📝 Solved Example

Q: If A:B = 2:3 and B:C = 4:5, find A:B:C.

1
Make B common: B appears as 3 and 4. LCM(3,4) = 12.
2
A:B = 2:3 = 8:12. B:C = 4:5 = 12:15.
3
A:B:C = 8:12:15
🧪 11 — Mixtures & Alligation

The Alligation (Cross) method is one of the most powerful shortcuts in aptitude. It works for mixing solutions, combining groups, and even average speed problems!

TCS Infosys
⚡ Alligation / Cross Method

To find the ratio of mixing two ingredients at concentrations (or prices) C1 and C2 to get a mean Cm:

Quantity of C1 : Quantity of C2 = |C2 − Cm| : |Cm − C1|

Works for prices, concentrations, averages, speeds — anything where you mix two groups!

🔢 Repeated Dilution
After removing X litres from V litres and replacing with water, N times:
Remaining = V × (1 − X/V)N

Example 1: Alligation

📝 Solved Example

Q: In what ratio must rice at Rs. 30/kg be mixed with rice at Rs. 42/kg to get a mixture worth Rs. 34/kg?

1
C1 = 30, C2 = 42, Cm = 34
2
Ratio = |42 − 34| : |34 − 30| = 8 : 4 = 2 : 1
3
Mix cheaper rice to costlier rice in ratio 2:1

Example 2: Repeated Dilution

📝 Solved Example

Q: A vessel contains 20L of milk. 4L is removed and replaced with water. This is done 3 times. How much milk remains?

1
Milk remaining = V × (1 − X/V)N = 20 × (1 − 4/20)³
2
= 20 × (4/5)³ = 20 × 64/125 = 10.24 litres
👤 12 — Ages

Age problems always reduce to simple linear equations. The key insight: the difference of ages remains constant regardless of time.

TCS Wipro Accenture
⚡ Key Insight

Age difference never changes. If father is 30 years older than son today, he'll be 30 years older forever. Use this to set up equations quickly.

Example 1: Ratio of Ages

📝 Solved Example

Q: The ages of A and B are in the ratio 3:5. After 4 years, their ratio becomes 2:3. Find their present ages.

1
Let ages = 3x and 5x.
2
(3x + 4)/(5x + 4) = 2/3. Cross multiply: 9x + 12 = 10x + 8
3
x = 4. Ages: A = 12 years, B = 20 years

Example 2: Years Ago Problem

📝 Solved Example

Q: 5 years ago, a father was 7 times as old as his son. 5 years from now, the father will be 3 times as old as the son. Find their current ages.

1
Let father = F, son = S. Equation 1: F − 5 = 7(S − 5) ⇒ F = 7S − 30
2
Equation 2: F + 5 = 3(S + 5) ⇒ F = 3S + 10
3
7S − 30 = 3S + 10 ⇒ 4S = 40 ⇒ S = 10. F = 3(10) + 10 = 40
4
Father = 40 years, Son = 10 years
🎲 13 — Permutations & Combinations

Permutation = arrangement (order matters). Combination = selection (order doesn't matter). The key is identifying which one the question needs.

TCS Infosys Wipro
🔢 Core Formulas
nPr = n! / (n−r)!     nCr = n! / [r!(n−r)!]
nCr = nC(n−r)     Circular: (n−1)!
Words with repeats: n! / (p! × q! × r!...)
⚡ Decision Guide
  • "How many ways to arrange?" → Permutation
  • "How many ways to select/choose?" → Combination
  • "At least one" → Total − None (complementary counting)
nnC2nC3
51010
61520
72135
82856
1045120
1266220

Example 1: Committee Formation

📝 Solved Example

Q: From a group of 6 men and 4 women, a committee of 5 is to be formed with at least 2 women. How many ways?

1
Cases with at least 2 women:
2W + 3M, or 3W + 2M, or 4W + 1M
2
4C2 × 6C3 = 6 × 20 = 120
4C3 × 6C2 = 4 × 15 = 60
4C4 × 6C1 = 1 × 6 = 6
3
Total = 120 + 60 + 6 = 186 ways

Example 2: Word Arrangement

📝 Solved Example

Q: How many different words can be formed from the letters of "MISSISSIPPI"?

1
Count letters: M=1, I=4, S=4, P=2. Total = 11
2
Arrangements = 11! / (1! × 4! × 4! × 2!)
3
= 39916800 / (1 × 24 × 24 × 2) = 39916800 / 1152 = 34,650
🎲 14 — Probability

Probability measures the chance of an event occurring (0 to 1). The #1 shortcut: for "at least one" questions, ALWAYS use 1 − P(none).

TCS Infosys Wipro
🔢 Core Formulas
P(Event) = Favorable outcomes / Total outcomes
P(A or B) = P(A) + P(B) − P(A and B)
P(at least one) = 1 − P(none)
Independent events: P(A and B) = P(A) × P(B)
⚡ Key Values to Memorize
ScenarioProbability
Sum of 7 with two dice6/36 = 1/6 (most likely sum)
Getting a doublet6/36 = 1/6
Drawing an ace from 52 cards4/52 = 1/13
Drawing a face card12/52 = 3/13

Example 1: At Least One (Complementary)

📝 Solved Example

Q: A coin is tossed 4 times. What is the probability of getting at least one head?

1
Use complement: P(at least 1 head) = 1 − P(no heads)
2
P(no heads) = P(all tails) = (1/2)&sup4; = 1/16
3
P(at least 1 head) = 1 − 1/16 = 15/16

Example 2: Cards

📝 Solved Example

Q: Two cards are drawn from a standard 52-card deck. What is the probability that both are aces?

1
Ways to pick 2 aces from 4: 4C2 = 6
2
Ways to pick any 2 cards from 52: 52C2 = 1326
3
P = 6/1326 = 1/221
🔄 15 — Number Series

Number series tests pattern recognition. The trick is having a systematic approach rather than guessing randomly.

TCS Infosys Cognizant
⚡ Pattern Detection Strategy
  1. Differences: Write differences between consecutive terms
  2. Second differences: If first differences aren't obvious, take differences of differences
  3. Ratios: Check if consecutive terms have a common ratio
  4. Alternating: Check odd-position and even-position terms separately
  5. Known sequences: Squares, cubes, primes, triangular numbers, Fibonacci
🔢 Common Sequences to Recognize
TypeSequence
Triangular1, 3, 6, 10, 15, 21, 28, 36, 45, 55...
Fibonacci1, 1, 2, 3, 5, 8, 13, 21, 34, 55...
Primes2, 3, 5, 7, 11, 13, 17, 19, 23, 29...
n² + 12, 5, 10, 17, 26, 37, 50...
1, 8, 27, 64, 125, 216, 343...

Example 1: Difference Pattern

📝 Solved Example

Q: Find the next number: 2, 5, 10, 17, 26, ?

1
First differences: 3, 5, 7, 9 (consecutive odd numbers!)
2
Next difference = 11. Answer = 26 + 11 = 37
3
Pattern revealed: n² + 1 for n = 1,2,3,4,5,6 → 2,5,10,17,26,37

Example 2: Alternating Series

📝 Solved Example

Q: Find the next number: 3, 8, 6, 14, 12, 20, ?

1
Check alternating positions:
Odd positions: 3, 6, 12 → each ×2!
Even positions: 8, 14, 20 → +6 each time
2
Next is odd position (7th): 12 × 2 = 24
📋 16 — Logarithms

Logarithm questions test your knowledge of properties. Memorize the rules and common log values, and most problems become straightforward.

TCS Infosys
🔢 Properties (Must Memorize)
PropertyFormula
Product Rulelog(ab) = log a + log b
Quotient Rulelog(a/b) = log a − log b
Power Rulelog(an) = n · log a
Base Changelogab = log b / log a = 1/logba
Identitylogaa = 1
Log of 1loga1 = 0
⚡ Common Values

log10 2 = 0.3010 | log10 3 = 0.4771 | log10 5 = 0.6990 | log10 7 = 0.8451

Useful: Number of digits in N = floor(log10 N) + 1

⚠ Common Trap

log(a + b) ≠ log a + log b. There is NO shortcut for log of a sum!

Example 1: Simplification

📝 Solved Example

Q: Find the value of log28 + log381 − log525

1
log28 = log22³ = 3
2
log381 = log33&sup4; = 4
3
log525 = log55² = 2
4
Answer = 3 + 4 − 2 = 5

Example 2: Number of Digits

📝 Solved Example

Q: How many digits are there in 250? (Given: log 2 = 0.3010)

1
log10(250) = 50 × log 2 = 50 × 0.3010 = 15.05
2
Number of digits = floor(15.05) + 1 = 15 + 1 = 16 digits
17 — Surds & Indices

Exponent rules and rationalization are the two pillars here. Questions are typically about simplification and comparison.

TCS Infosys
🔢 Exponent Rules
RuleFormula
Multiplicationam × an = am+n
Divisionam / an = am−n
Power of power(am)n = amn
Zero exponenta0 = 1
Negativea−n = 1/an
Fractionalam/n = n√(am)
⚡ Rationalization
1/(√a + √b) = (√a − √b) / (a − b)

Tip: Multiply by the conjugate to remove surds from the denominator.

Useful values: √2 = 1.414 | √3 = 1.732 | √5 = 2.236 | √7 = 2.646

Example 1: Simplification

📝 Solved Example

Q: Simplify: (27)2/3 × (8)−1/3

1
(27)2/3 = (3³)2/3 = 3² = 9
2
(8)−1/3 = (2³)−1/3 = 2−1 = 1/2
3
Answer = 9 × 1/2 = 9/2 = 4.5

Example 2: Comparing Surds

📝 Solved Example

Q: Which is greater: √3 or ³√4?

1
LCM of root indices (2 and 3) = 6. Raise both to power 6.
2
(√3)6 = 3³ = 27. (³√4)6 = 4² = 16.
3
27 > 16, so √3 > ³√4
📅 18 — Calendar

Calendar problems use the "odd days" method. Once you memorize the odd-day counts, finding the day of any date becomes mechanical.

TCS Cognizant
🔢 Odd Days Reference
PeriodOdd Days
Ordinary year (365 days)1
Leap year (366 days)2
100 years5
200 years3
300 years1
400 years0

Day codes: 0=Sun, 1=Mon, 2=Tue, 3=Wed, 4=Thu, 5=Fri, 6=Sat

Month odd days: Jan=3, Feb=0(1 leap), Mar=3, Apr=2, May=3, Jun=2, Jul=3, Aug=3, Sep=2, Oct=3, Nov=2, Dec=3

⚡ Leap Year Rules
  • Divisible by 4 → Leap year
  • Divisible by 100 → NOT a leap year
  • Divisible by 400 → IS a leap year
  • Examples: 2000 (leap), 1900 (not leap), 2024 (leap)

Example 1: Find the Day

📝 Solved Example

Q: What day of the week was 15th August 1947?

1
Odd days from years:
1600 years = 0 odd days
300 years = 1 odd day
46 years = 11 leap + 35 ordinary = 22 + 35 = 57 odd days. 57 mod 7 = 1
Total from years = 0 + 1 + 1 = 2
2
Odd days from months (Jan to Jul):
3 + 0 + 3 + 2 + 3 + 2 + 3 = 16. 16 mod 7 = 2
3
Days: 15 mod 7 = 1
4
Total = 2 + 2 + 1 = 5 = Friday

Example 2: Next Year's Day

📝 Solved Example

Q: If January 1, 2023 is a Sunday, what day is January 1, 2024?

1
2023 is an ordinary year (not divisible by 4) → 1 odd day
2
Sunday + 1 = Monday
💡 Quick Rule

Ordinary year: next year's same date = +1 day. Leap year: +2 days.

🕘 19 — Clocks

All clock problems can be solved with one magic formula. Memorize it and you'll never struggle with clock angles again.

TCS Infosys
🔢 The Master Formula
Angle = |30H − (11/2)M| degrees

Where H = hour, M = minutes. If result > 180°, subtract from 360°.

⚡ Quick Facts
  • Hands overlap 11 times in 12 hours (every 65.45 minutes)
  • Hands are at right angles (90°) 22 times in 12 hours
  • Hands are in straight line (180°) 11 times in 12 hours
  • Minute hand gains 5.5 degrees per minute over the hour hand

Example 1: Find the Angle

📝 Solved Example

Q: What is the angle between the hour and minute hand at 3:20?

1
Angle = |30H − (11/2)M| = |30(3) − (11/2)(20)|
2
= |90 − 110| = |−20| = 20 degrees

Example 2: When Do Hands Overlap?

📝 Solved Example

Q: At what time between 4 and 5 o'clock do the hour and minute hands overlap?

1
Overlap means angle = 0°. Set |30(4) − (11/2)M| = 0
2
120 = (11/2)M ⇒ M = 240/11 = 21 and 9/11 minutes
3
Hands overlap at 4:21:49 (approximately 4:21 and 49 seconds)
20 — Simplification & Approximation

Simplification tests your ability to solve complex arithmetic expressions quickly using BODMAS and estimation. Approximation is about finding near-accurate answers rapidly when exact calculation is time-consuming.

TCS Infosys All Companies
Core Formulas
BODMAS: Brackets → Orders (powers) → Division → Multiplication → Addition → Subtraction
(a + b)² = a² + 2ab + b²  |  (a − b)² = a² − 2ab + b²
a² − b² = (a + b)(a − b)
Key Shortcuts
  • Round to nearest 10: 49.8 ≈ 50, 101.3 ≈ 100. Adjust the error at the end.
  • Fraction trick: 999 ÷ 7 ≈ 1000 ÷ 7 ≈ 142.8 (close enough for MCQs)
  • Square root approx: √50 is between √49=7 and √64=8, closer to 7, so ≈7.07
  • Percentage to decimal: Instantly convert for multiplication — 37.5% = 0.375

Example 1: BODMAS Application

Solved Example Easy

Q: Simplify: 36 ÷ 4 + 3 × 2 − (8 − 3)

1
Brackets: (8 − 3) = 5
2
Division & Multiplication (left to right): 36 ÷ 4 = 9, then 3 × 2 = 6
3
Addition & Subtraction: 9 + 6 − 5 = 10

Example 2: Approximation

Solved Example Medium

Q: Find the approximate value of: 4999 ÷ 49.8 + 201.3 × 9.9

1
Round: 4999 ≈ 5000, 49.8 ≈ 50, 201.3 ≈ 200, 9.9 ≈ 10
2
5000 ÷ 50 + 200 × 10 = 100 + 2000 = ≈ 2100
3
Exact: 100.38 + 1992.87 = 2093.25. Our approx of 2100 is close enough to pick the right MCQ option.

Example 3: Algebraic Identity Shortcut

Solved Example Hard

Q: Find: (478)² − (322)²

1
Identity: a² − b² = (a+b)(a−b)
2
(478 + 322)(478 − 322) = 800 × 156
3
800 × 156 = 800 × 150 + 800 × 6 = 120000 + 4800 = 124,800
Common Trap

Never try to compute 478² and 322² separately — it wastes time and invites errors. Always check for algebraic identities first.

Pro Tip

In approximation questions, check how spread apart the answer options are. If options are 2000, 2100, 2200, 2300 — rough rounding works. If options are 2093, 2097, 2101, 2107 — you need more precision.

21 — Partnerships

Partnership questions deal with sharing profits (or losses) among business partners based on their capital investment and the duration for which they invested.

Wipro Cognizant Accenture
Core Formulas
Profit share ratio = CapitalA × TimeA : CapitalB × TimeB
A's share = Total Profit × (A's investment ratio / Sum of all ratios)
Key Shortcuts
  • Equal time: Profit ratio = Capital ratio directly
  • Equal capital: Profit ratio = Time ratio directly
  • Working partner bonus: Deduct the salary/bonus first, then divide remaining profit in ratio

Example 1: Simple Partnership

Solved Example Easy

Q: A and B invest Rs. 40,000 and Rs. 60,000 respectively. If the total profit is Rs. 25,000, find A's share.

1
Ratio: A : B = 40000 : 60000 = 2 : 3
2
A's share = 25000 × 2/5 = Rs. 10,000

Example 2: Varying Investment Periods

Solved Example Medium

Q: A invests Rs. 30,000 for 12 months. B invests Rs. 45,000 for 8 months. Profit is Rs. 18,000. Find B's share.

1
A's effective = 30000 × 12 = 360000. B's effective = 45000 × 8 = 360000.
2
Ratio = 360000 : 360000 = 1 : 1
3
B's share = 18000 × 1/2 = Rs. 9,000

Example 3: Working Partner Salary

Solved Example Hard

Q: A and B invest Rs. 50,000 and Rs. 30,000 respectively. A manages the business and gets 10% of profit as salary. Remaining profit is split in capital ratio. Total profit is Rs. 40,000. Find A's total earnings.

1
A's salary = 10% of 40000 = Rs. 4000
2
Remaining = 40000 − 4000 = 36000
3
Ratio = 50000 : 30000 = 5 : 3. A's profit share = 36000 × 5/8 = 22500
4
A's total = 4000 + 22500 = Rs. 26,500
22 — Boats & Streams

Boats & Streams is a special case of speed problems where the water current aids or opposes the boat's motion. Master the 4 key formulas and these become easy marks.

TCS Infosys Wipro
Core Formulas
Downstream speed = Boat speed + Stream speed = (u + v)
Upstream speed = Boat speed − Stream speed = (u − v)
Boat speed (still water) = (Downstream + Upstream) / 2
Stream speed = (Downstream − Upstream) / 2
Key Shortcuts
  • If time taken is same upstream and downstream: Distance ratio = Speed ratio (downstream : upstream)
  • Round trip (same distance): Average speed = (u² − v²) / u, where u = boat speed, v = stream speed
  • Still water questions: Stream speed = 0, so just use Distance = Speed × Time

Example 1: Finding Speed

Solved Example Easy

Q: A boat goes 20 km downstream in 2 hours and returns in 4 hours. Find the speed of the boat in still water and the speed of the stream.

1
Downstream speed = 20/2 = 10 km/hr. Upstream speed = 20/4 = 5 km/hr.
2
Boat speed = (10 + 5)/2 = 7.5 km/hr
3
Stream speed = (10 − 5)/2 = 2.5 km/hr

Example 2: Distance Covered

Solved Example Medium

Q: A man can row at 8 km/hr in still water. If the river flows at 2 km/hr, how long will he take to row 30 km upstream and return?

1
Upstream speed = 8 − 2 = 6 km/hr. Downstream speed = 8 + 2 = 10 km/hr.
2
Time upstream = 30/6 = 5 hrs. Time downstream = 30/10 = 3 hrs.
3
Total = 5 + 3 = 8 hours

Example 3: Stream Speed From Round Trip

Solved Example Hard

Q: A boat takes 6 hours to travel 36 km downstream and 36 km upstream. If the boat speed in still water is 9 km/hr, find the stream speed.

1
Let stream speed = v. Downstream = (9+v), Upstream = (9−v).
2
36/(9+v) + 36/(9−v) = 6
3
36(9−v) + 36(9+v) = 6(9+v)(9−v) → 36(18) = 6(81−v²) → 648 = 486 − 6v²
4
6v² = 486 − 648 = ... Wait, 648 > 486 gives negative. Let me recheck: 36×18 = 648. 6(81−v²) = 486−6v². So 648 = 486−6v² means −6v² = 162, impossible. The total time 6 hours is too short — let's use 10 hours instead for a valid question: 36/(9+v)+36/(9−v)=10 → 648=10(81−v²) → 810−10v²=648 → v²=16.2... Let's pick cleaner numbers: Total = 8 hrs. 648 = 8(81−v²) = 648−8v² → 8v²=0. Still off. Clean version: 24km each way. 24/(9+v)+24/(9−v)=6 → 24(18)/(81−v²)=6 → 432=6(81−v²) → 72=81−v² → v²=9 → v=3 km/hr
Common Trap

Always check that your numbers give a valid equation. If you get a negative under the square root or impossible time, recheck the question setup.

23 — Data Interpretation

Data Interpretation (DI) questions present data in tables, charts, or graphs. You must extract, calculate, and compare values. Speed and approximation skills are critical here.

TCS Infosys All Companies
Core Formulas
Percentage share = (Individual value / Total) × 100
Growth rate = [(New − Old) / Old] × 100
Average = Sum of values / Number of values
Ratio = Value A : Value B (simplify by dividing common factor)
Key Shortcuts
  • Bar chart: Estimate bar heights visually before calculating — eliminates 2 options instantly
  • Pie chart: 1% of 360° = 3.6°. So 25% = 90°, 50% = 180°
  • Line graph: Steepest slope = highest growth rate. Flat = no change.
  • Caselet: Draw a rough table from the text data before solving

Use this data for Examples 1-3:

Department2022 Revenue (Lakhs)2023 Revenue (Lakhs)Employees
Sales12015040
IT20024060
HR807220
Marketing10013030
Total500592150

Example 1: Percentage Share

Solved Example Easy

Q: What percentage of total 2023 revenue comes from IT?

1
IT revenue 2023 = 240. Total = 592.
2
% share = (240/592) × 100 ≈ 40.54%

Example 2: Growth Rate

Solved Example Medium

Q: Which department had the highest growth rate from 2022 to 2023?

1
Sales: (150−120)/120 × 100 = 25%
2
IT: (240−200)/200 × 100 = 20%
3
HR: (72−80)/80 × 100 = −10% (decline)
4
Marketing: (130−100)/100 × 100 = 30%. Marketing has the highest growth (30%)

Example 3: Revenue Per Employee

Solved Example Hard

Q: Which department has the highest revenue per employee in 2023? What is the ratio of highest to lowest?

1
Sales: 150/40 = 3.75 L. IT: 240/60 = 4 L. HR: 72/20 = 3.6 L. Marketing: 130/30 = 4.33 L.
2
Marketing has the highest (4.33 L/employee). HR has the lowest (3.6 L/employee).
3
Ratio = 4.33 : 3.6 = 433 : 360 ≈ 1.2 : 1
Pro Tip

In DI, speed is everything. Don't calculate exact values unless the options are very close. Use approximation first, then refine only if needed. Also, read ALL questions for a data set before starting — later questions sometimes reveal patterns useful for earlier ones.

🔐 24 — Coding & Decoding

Coding-Decoding tests pattern recognition. You're given a rule that transforms one word/number into another and must apply the same rule.

TCS Infosys Wipro
⚡ Common Coding Patterns
  • Letter shifting: Each letter moves forward/backward by a fixed number (A+2=C, B+2=D...)
  • Reverse order: WORD becomes DROW
  • Position-based: Letter number in alphabet (A=1, B=2, ... Z=26)
  • Mirror coding: A↔Z, B↔Y, C↔X (position sums to 27)
  • Number substitution: Each letter replaced by its position number
  • Vowel/consonant based: Different rules for vowels vs consonants

Example 1: Letter Shifting

📝 Solved Example

Q: If COMPUTER is coded as DPNQVUFS, how is LAPTOP coded?

1
Find the pattern: C→D (+1), O→P (+1), M→N (+1)... Each letter shifted +1
2
L→M, A→B, P→Q, T→U, O→P, P→Q
3
LAPTOP = MBQUPQ

Example 2: Mirror Coding

📝 Solved Example

Q: In a code, APPLE is written as ZKKOV. How is MANGO written?

1
Check pattern: A(1)→Z(26), sum=27. P(16)→K(11), sum=27. Mirror coding!
2
Rule: Each letter maps to (27 − position). M(13)→N(14). A(1)→Z(26). N(14)→M(13). G(7)→T(20). O(15)→L(12).
3
MANGO = NZMTL
👪 25 — Blood Relations

Blood relation problems test your ability to trace family connections. Drawing a family tree is the most reliable approach.

TCS Wipro Cognizant
⚡ Quick Reference
RelationMeaning
Father's/Mother's sonBrother
Father's/Mother's daughterSister
Father's brotherUncle (Paternal)
Mother's brotherUncle (Maternal)
Father's/Mother's fatherGrandfather
Son's wifeDaughter-in-law
Daughter's husbandSon-in-law
Brother's/Sister's sonNephew
Brother's/Sister's daughterNiece

Key tip: Always draw the family tree! Use arrows for parent-child and lines for siblings/spouse.

Example 1

📝 Solved Example

Q: Pointing to a photograph, Arun says "She is the daughter of my grandfather's only son." How is the girl related to Arun?

1
Grandfather's only son = Arun's father
2
Daughter of Arun's father = Arun's sister

Example 2

📝 Solved Example

Q: A is the mother of B. B is the sister of C. D is the son of C. E is the brother of D. How is A related to E?

1
A → mother of B. B is sister of C, so A is mother of C too.
2
D is son of C (A's grandchild). E is brother of D (also A's grandchild).
3
A is E's grandmother
💺 26 — Seating Arrangement & Directions

Seating and direction problems require spatial visualization. Draw diagrams — always!

TCS Infosys Wipro
⚡ Direction Basics

Remember: North(up), East(right), South(down), West(left).

  • Turn right from North = East
  • Turn left from North = West
  • Opposite of North-East = South-West
  • Pythagoras: Final distance = √(horizontal² + vertical²)
⚡ Circular Seating Tips
  • Facing center: Right of person = your left when looking at diagram
  • Facing outside: Everything reverses
  • Start with the most constrained clue first
  • Use definite clues before relative ones

Example 1: Direction

📝 Solved Example

Q: A man walks 3 km North, turns right and walks 4 km, then turns right and walks 3 km. How far is he from the starting point?

1
3 km North, then right (East) 4 km, then right (South) 3 km.
2
The 3 km N and 3 km S cancel out. He is purely 4 km East of start.
3
Distance from start = 4 km

Example 2: Linear Seating

📝 Solved Example

Q: Five people A, B, C, D, E sit in a row facing north. B sits to the right of A. D sits at the extreme right. C sits between A and D. Who sits in the middle?

1
D is at extreme right (position 5). B is right of A.
2
C sits between A and D. Since D is at position 5, we need A_C_D pattern.
3
Arrangement: E, A, B, C, D (B is right of A, C is between A and D).
4
Middle (position 3) = B
27 — Syllogisms

Syllogisms are logical arguments where conclusions are drawn from two or more premises. You must determine if a conclusion logically follows from the given statements, regardless of real-world truth. Use Venn diagrams to solve.

All Companies
Statement Types & Venn Representations
StatementVenn DiagramConverse
All A are BA circle completely inside BSome B are A (valid)
No A are BA and B don't overlapNo B are A (valid)
Some A are BA and B partially overlapSome B are A (valid)
Some A are not BPart of A is outside BNo valid converse
Key Rules
  • "All A are B" does NOT mean "All B are A"
  • "All A are B" DOES imply "Some A are B" and "Some B are A"
  • "No A are B" = "No B are A" (fully reversible)
  • A conclusion follows ONLY if it is true in ALL possible valid Venn diagrams
  • "Either I or II follows" when I and II are complementary (one must be true)

Example 1: All-All Chain

Solved Example Easy

Q: Statements: All dogs are animals. All animals are living beings. Conclusions: (I) All dogs are living beings. (II) Some living beings are dogs.

1
Draw: Dogs inside Animals inside Living Beings (nested circles).
2
I: All dogs are living beings → True (Dogs is inside Living Beings).
3
II: Some living beings are dogs → True (the dog portion exists inside living beings).
4
Both I and II follow.

Example 2: Some-No Combination

Solved Example Medium

Q: Statements: Some cats are dogs. No dogs are birds. Conclusions: (I) No cats are birds. (II) Some cats are not birds.

1
"Some cats are dogs" → overlap between Cats and Dogs.
2
"No dogs are birds" → Dogs and Birds don't overlap.
3
I: "No cats are birds" → Not necessarily true. Cats that are NOT dogs might still be birds. Draw it: possible that non-dog cats overlap with birds.
4
II: "Some cats are not birds" → True. The cats that ARE dogs cannot be birds (since no dogs are birds). So at least some cats are not birds.
5
Only II follows.

Example 3: Complementary Pair

Solved Example Hard

Q: Statements: All pens are books. Some books are erasers. Conclusions: (I) All erasers are pens. (II) Some erasers are not pens.

1
Pens inside Books. Erasers partially overlap Books.
2
I: "All erasers are pens" — possible in one diagram (if erasers fully inside pens), but NOT necessary. Can draw diagram where erasers overlap books but NOT pens. So I does NOT definitely follow.
3
II: "Some erasers are not pens" — also NOT definitely true (if all erasers happen to be pens).
4
But I and II are complementary: "All erasers are pens" vs "Some erasers are not pens" — one of them MUST be true. Either I or II follows.
Common Trap

When neither conclusion follows individually, check if they form a complementary pair (All vs Some...not). If yes, "Either I or II follows" is the answer.

28 — Puzzles

Puzzle questions give a set of conditions about arrangements (seating, floors, scheduling) and ask you to deduce the complete arrangement. These are time-consuming but high-scoring if solved correctly.

Cognizant Wipro Infosys
Approach
  • Read ALL clues first before placing anyone
  • Start with definite clues (e.g., "A sits at the left end")
  • Use elimination: If A can't be in positions 2 or 3, and position 1 is taken, A must be in 4 or 5
  • Try case analysis: If stuck, assume two possible cases and test each against remaining clues
  • Verify: After completing, check ALL conditions once more

Example 1: Linear Arrangement

Solved Example Easy

Q: Five friends P, Q, R, S, T sit in a row facing North. R is in the middle. P is to the immediate left of R. T is at the right end. Who is between Q and T?

1
5 positions: _ _ _ _ _. R is in position 3 (middle). T is in position 5 (right end).
2
P is immediate left of R → P is in position 2. So: _ P R _ T
3
Q and S fill positions 1 and 4. Between Q and T: if Q is at 1, between Q and T = P, R, S. If Q is at 4, between Q and T = nobody (adjacent).
4
Since Q and S are remaining: Q=1, S=4 or Q=4, S=1. Either way, S is between Q and T (position 4) in the more logical reading.

Example 2: Circular Arrangement

Solved Example Medium

Q: Six people A, B, C, D, E, F sit around a circular table facing the center. A is opposite D. B is to the immediate right of A. C is not adjacent to D. Where does F sit?

1
Fix A at top. D is opposite A (bottom). 6 seats in circle: A, _, _, D, _, _
2
B is immediate right of A. Clockwise: A, B, _, D, _, _
3
C is not adjacent to D. Seats adjacent to D are positions 3 and 5. So C must be in position 6. Arrangement: A, B, _, D, _, C
4
E and F fill positions 3 and 5. F sits in position 3 or 5 (either left of D or between C and A).

Example 3: Floor Arrangement

Solved Example Hard

Q: 5 people (A-E) live on floors 1-5 (ground=1, top=5). B lives above A. C lives on floor 3. D lives immediately below E. A does not live on floor 1. Find the arrangement.

1
C is on floor 3 (fixed). D is immediately below E, so D-E are consecutive with E higher.
2
Possible D-E pairs: (1,2), (2,3)—but 3 is C, so no. (4,5). So D-E is either floors 1-2 or 4-5.
3
B lives above A, and A is not on floor 1. If D-E = floors 4-5, then A and B fill floors 1 and 2. But A ≠ floor 1, so A=2, B must be above A = floor 4 or 5, but those are D and E. Contradiction.
4
So D-E = floors 1-2 (D=1, E=2). A and B fill floors 4 and 5. A ≠ 1 (satisfied). B above A → A=4, B=5. Final: D(1), E(2), C(3), A(4), B(5)
29 — Data Sufficiency

Data Sufficiency tests whether the given statements provide enough information to answer a question. You don't need to solve the problem — just determine if it CAN be solved. This is a favourite in Morgan Stanley and CAT exams.

Infosys Morgan Stanley
Standard Answer Choices
ChoiceMeaning
(A)Statement I alone is sufficient
(B)Statement II alone is sufficient
(C)Both together are sufficient, but neither alone
(D)Each alone is sufficient
(E)Neither alone nor together is sufficient
Approach
  • Step 1: Consider Statement I alone. Can you answer? If yes, eliminate B, C, E.
  • Step 2: Consider Statement II alone (forget Statement I). Can you answer? If yes, eliminate A, C, E.
  • Step 3: If neither alone works, combine them. If combined works → C. If not → E.
  • Don't solve: Just determine sufficiency. Saves time.

Example 1: Statement I Sufficient

Solved Example Easy

Q: What is the value of x? (I) x + 5 = 12. (II) x is a prime number less than 10.

1
Statement I: x + 5 = 12 → x = 7. Unique value. Sufficient.
2
Statement II: x is prime and <10 → x could be 2, 3, 5, or 7. Not unique. Not sufficient.
3
Answer: (A) — Statement I alone is sufficient.

Example 2: Both Together Needed

Solved Example Medium

Q: Is x > y? (I) x = 2y − 3. (II) y = 5.

1
Statement I: x = 2y − 3. Without knowing y, x could be anything. If y=1, x=−1 (x<y). If y=5, x=7 (x>y). Not sufficient.
2
Statement II: y = 5. But we don't know x. Not sufficient.
3
Together: x = 2(5) − 3 = 7, y = 5. x > y → Yes. Answer: (C)

Example 3: Neither Sufficient

Solved Example Hard

Q: What is the area of triangle ABC? (I) AB = 10 cm. (II) Angle A = 60°.

1
Statement I: One side given. Need height or two more sides. Not sufficient.
2
Statement II: One angle given. Need sides. Not sufficient.
3
Together: One side + one angle. Still not enough (need at least one more side to compute area). Answer: (E)
Common Trap

Don't assume a triangle is equilateral, right-angled, or isosceles unless explicitly stated. With one side and one angle, infinite triangles are possible.

30 — Input-Output

Input-Output questions show a "machine" that rearranges numbers or words in each step following a hidden rule. You must discover the rule and predict intermediate or final steps.

Wipro Cognizant
How to Approach
  • Compare Input with Step 1: What changed? Which element moved? Where did it go?
  • Compare Step 1 with Step 2: Same rule or different?
  • Common patterns: Sorting (ascending/descending), alternating smallest/largest to ends, alphabetical rearrangement
  • Track one element: Follow where a single number/word moves across steps

Example 1: Number Sorting

Solved Example Easy

Q: Input: 45 12 78 33 9 56. Step 1: 9 45 12 78 33 56. Step 2: 9 12 45 78 33 56. Step 3: 9 12 33 45 78 56. Step 4: 9 12 33 45 56 78. What is the rule?

1
Step 1: smallest (9) moved to left. Step 2: next smallest (12) placed correctly. Step 3: 33 placed. Step 4: 56 placed.
2
Rule: In each step, the smallest unsorted element is picked and placed at its correct position (insertion sort from left).
3
The output (final sorted) = 9 12 33 45 56 78.

Example 2: Word Rearrangement

Solved Example Medium

Q: Input: go set map bit ace top. Step 1: ace go set map bit top. Step 2: ace bit go set map top. Step 3: ace bit go map set top. What is Step 4?

1
Step 1: "ace" (alphabetically first) moved to front. Step 2: "bit" (next alphabetically) moved to position 2. Step 3: "go" already at 3, "map" moved to position 4.
2
Rule: Alphabetical sorting, one word placed correctly per step from left to right.
3
Step 4: "set" and "top" need ordering. set < top alphabetically. Step 4: ace bit go map set top (final output, fully sorted).

Example 3: Alternating Pattern

Solved Example Hard

Q: Input: 14 7 32 19 5 28. Step 1: 5 14 7 32 19 28. Step 2: 5 14 7 19 28 32. Step 3: 5 7 14 19 28 32. What is the pattern?

1
Step 1: Smallest (5) moved to leftmost. Step 2: Largest remaining (32) moved to rightmost.
2
Step 3: Next smallest (7) placed at position 2, rest shifted. Pattern alternates: smallest to left, largest to right, repeat.
3
Rule: Odd steps pick the smallest unsorted to left end. Even steps pick the largest unsorted to right end. Converges to sorted order.
Common Trap

Don't assume simple ascending/descending sort. Many input-output machines alternate between picking smallest and largest, or sort words and numbers by different rules simultaneously.

📑 Formula Cheat Sheet

Quick-reference card of the most important formulas. Bookmark this for last-minute revision!

TopicKey Formula
LCM & HCFLCM × HCF = a × b
PercentagesSuccessive: a + b + ab/100
Profit & LossNet P% = Markup% − Discount% − (M×D/100)
Simple InterestSI = PRT/100
Compound InterestA = P(1+R/100)T
CI − SI (2 yrs)P(R/100)²
Rule of 72Doubling time = 72/R
Time & WorkTogether = ab/(a+b) days
Average Speed2ab/(a+b) for equal distances
TrainsTime = Total length / Relative speed
Pipes (leak)Leak time = ab/(b−a)
AlligationRatio = |C2−Cm| : |Cm−C1|
Repeated DilutionV(1 − X/V)N
Clock Angle|30H − 11M/2|
CalendarOrdinary year = 1 odd day, Leap = 2
ProbabilityP(at least 1) = 1 − P(none)
P & CnCr = n!/[r!(n−r)!]
Logarithmlog(an) = n.log(a)
Boats & StreamsStill water speed = (D+U)/2, Stream = (D−U)/2
PartnershipProfit ratio = CapitalA×TimeA : CapitalB×TimeB
Simplificationa²−b² = (a+b)(a−b)
🏢 Company-wise Exam Pattern

Different companies emphasize different topics. Here's what to prioritize based on your target company.

CompanyExam NameHigh-Priority TopicsTips
TCS TCS NQT Number Series, Percentages, P&L, Time & Work, Probability, Clocks, Calendar Moderate difficulty. Focus on speed. ~25-30 questions in 40 min.
Infosys InfyTQ Percentages, Profit/Loss, Time-Speed-Distance, P&C, Probability, Logarithms Slightly harder math. Practice DI sets.
Wipro NLTH Time & Work, Speed & Distance, Averages, Blood Relations, Coding-Decoding Mix of quant + logical. Medium difficulty.
Cognizant GenC / GenC Next Number Systems, Percentages, P&L, Ratio, Averages, Seating GenC is easier than GenC Next. Focus on fundamentals.
Accenture Accenture Assessment Percentages, Profit/Loss, Time & Work, Ages, Blood Relations Relatively easier. Speed is key — lots of questions, less time.
Capgemini Game-based Logical Reasoning, Number Series, Coding, Spatial Reasoning Unique game-based format. Practice spatial & pattern games.
Morgan Stanley Online Assessment + Interviews Probability, P&C, Puzzles, Number Theory, Data Interpretation, Logical Reasoning, Mental Ability High difficulty. Strong focus on quant & puzzles. Expect brain-teasers in interviews. See detailed breakdown below.
Deloitte Deloitte Assessment Quantitative Aptitude, Logical Reasoning, Verbal Ability, Business Scenarios Moderate difficulty. Strong verbal section. Case-study based DI sets.
Goldman Sachs HackerRank + Interviews Probability, P&C, Number Theory, Puzzles, Data Structures, Algorithms Very high difficulty. Focus on mathematical reasoning and coding. Expect brain-teasers.
Amazon Online Assessment Logical Reasoning, Data Interpretation, Coding (2-3 problems), Work Simulation Heavy coding focus. Aptitude is secondary but still tested. Leadership principles matter in interviews.

Morgan Stanley — Detailed Exam Pattern

Morgan Stanley is one of the most sought-after companies in campus placements, especially for technology and finance roles. Their selection process is rigorous and consists of multiple rounds designed to test mathematical aptitude, logical thinking, coding ability, and domain knowledge.

Selection Process Overview

RoundFormatDurationDetails
Round 1: Online Assessment MCQ + Coding 90–120 minutes Aptitude (Quant + Logical) + 2–3 coding problems. Conducted on HackerRank or similar platforms.
Round 2: Technical Interview 1 Face-to-face / Virtual 45–60 minutes DSA, OOP concepts, DBMS, OS. May include live coding on a whiteboard.
Round 3: Technical Interview 2 Face-to-face / Virtual 45–60 minutes Advanced problem-solving, system design (for experienced roles), puzzles, and brain-teasers.
Round 4: HR / Managerial Round Discussion 30–45 minutes Behavioural questions, situational judgement, "Why Morgan Stanley?", strengths/weaknesses.

Online Assessment — Aptitude Section Breakdown

Topic AreaWeightageDifficultyKey Sub-topics
Quantitative Aptitude ~40% High Probability, P&C, Number Theory (divisibility, remainders, modular arithmetic), Algebra, Percentages, Ratio & Proportion, SI/CI
Logical Reasoning ~25% Medium–High Puzzles (seating, scheduling), Syllogisms, Data Sufficiency, Blood Relations, Coding-Decoding
Data Interpretation ~15% Medium–High Tables, Bar/Line/Pie charts, Caselets. Requires quick calculation and approximation.
Verbal Ability ~10% Medium Reading Comprehension, Sentence Correction, Para Jumbles
Coding ~10% (separate) Medium–High 2–3 coding questions (arrays, strings, DP, graphs). Languages: C++, Java, Python.

Morgan Stanley — Most Frequently Asked Aptitude Topics

  1. Probability & P&C: Conditional probability, Bayes' theorem, dice/cards/balls problems, arrangement with restrictions. This is their #1 favourite topic.
  2. Number Theory: GCD/LCM, modular arithmetic, last digits of large powers, divisibility rules for large numbers, prime factorisation.
  3. Puzzles & Brain-Teasers: Classic puzzles like the "100 locker problem," "weighing 8 balls to find the heavier one," "crossing a bridge in minimum time." Expected in interviews, not just the written test.
  4. Data Interpretation: Complex multi-graph DI sets with 4–5 questions each. Requires speed and approximation skills.
  5. Time, Speed & Distance: Relative motion, trains, boats & streams, circular track meetings.
  6. Profit & Loss / Percentages: Multi-step problems involving successive discounts, marked price chains, partnerships.

Sample Morgan Stanley-Level Questions

Sample Q1 (Probability):

A bag contains 5 red, 4 blue, and 3 green balls. Three balls are drawn at random. What is the probability that exactly 2 are red?

Solution:

Total ways to pick 3 from 12 = 12C3 = 220

Ways to pick 2 red from 5 = 5C2 = 10

Ways to pick 1 non-red from 7 = 7C1 = 7

Favorable = 10 × 7 = 70

P = 70 / 220 = 7/22

Sample Q2 (Number Theory):

What is the remainder when 2^256 is divided by 17?

Solution (using Fermat's Little Theorem):

Since 17 is prime and gcd(2, 17) = 1, by Fermat's Little Theorem: 2^16 ≡ 1 (mod 17)

256 = 16 × 16, so 2^256 = (2^16)^16 ≡ 1^16 ≡ 1 (mod 17)

Remainder = 1

Sample Q3 (Classic Puzzle — asked in interviews):

You have 8 identical-looking balls. One is heavier than the rest. Using a balance scale, what is the minimum number of weighings needed to find the heavier ball?

Solution:

Divide into 3 groups: 3, 3, 2.

Weighing 1: Compare the two groups of 3.

  • If one side is heavier → the heavy ball is in that group of 3.
  • If balanced → the heavy ball is in the remaining group of 2.

Weighing 2:

  • If group of 3: weigh 1 vs 1 from that group. If balanced, the third is heavy. If not, the heavier side is the answer.
  • If group of 2: weigh 1 vs 1. The heavier one is the answer.

Answer: 2 weighings

💡 Morgan Stanley Preparation Tips
  • Probability is king: Spend extra time mastering conditional probability, Bayes' theorem, and combinatorics. At least 30% of their quant section involves these topics.
  • Practice puzzles separately: Keep a list of 50+ classic interview puzzles. Morgan Stanley interviewers love them, especially for technology roles.
  • Speed matters: The online test is time-pressured. Practice DI sets under timed conditions — aim for 2–3 minutes per DI question.
  • Don't ignore coding: Even if you're preparing for aptitude, the coding section is a hard filter. Practice medium-level LeetCode problems (arrays, strings, DP).
  • Brush up mental math: Morgan Stanley questions often involve large numbers. Knowing squares up to 30, cubes up to 15, and fraction-percentage conversions is essential.
  • Expect the unexpected: Interview questions can be open-ended ("How many tennis balls fit in this room?"). These test structured thinking, not exact answers.
💡 Universal Preparation Strategy
  1. Week 1-2: Master basics — Percentages, Ratio, Averages, Number Systems
  2. Week 3-4: Core problem-solving — Time & Work, Speed & Distance, P&L, Interest
  3. Week 5-6: Advanced topics — P&C, Probability, Series, Logarithms
  4. Week 7-8: Logical Reasoning & Mock Tests. Take at least 10 full-length mocks.

Daily practice: Solve 20-30 problems. Time yourself. Review mistakes. Repeat.